use "|" as sed delimiter if pattern has "/" (#1118)

removes the need for "/" to be escaped with a backslash
This commit is contained in:
i-c-u-p
2022-06-15 15:03:25 +00:00
committed by GitHub
parent 6207180f7b
commit b63045a0c0
3 changed files with 6 additions and 6 deletions

View File

@@ -12,9 +12,9 @@ case "$(printf "Copy URL\\nsxiv\\nsetbg\\nPDF\\nbrowser\\nlynx\\nvim\\nmpv\\nmpv
"queue yt-dlp") qndl "$feed" >/dev/null 2>&1 ;;
"queue yt-dlp audio") qndl "$feed" 'yt-dlp --embed-metadata -icx -f bestaudio/best' >/dev/null 2>&1 ;;
"queue download") qndl "$feed" 'curl -LO' >/dev/null 2>&1 ;;
PDF) curl -sL "$feed" > "/tmp/$(echo "$feed" | sed "s/.*\///;s/%20/ /g")" && zathura "/tmp/$(echo "$feed" | sed "s/.*\///;s/%20/ /g")" >/dev/null 2>&1 ;;
sxiv) curl -sL "$feed" > "/tmp/$(echo "$feed" | sed "s/.*\///;s/%20/ /g")" && sxiv -a "/tmp/$(echo "$feed" | sed "s/.*\///;s/%20/ /g")" >/dev/null 2>&1 ;;
vim) curl -sL "$feed" > "/tmp/$(echo "$feed" | sed "s/.*\///;s/%20/ /g")" && setsid -f "$TERMINAL" -e "$EDITOR" "/tmp/$(echo "$feed" | sed "s/.*\///;s/%20/ /g")" >/dev/null 2>&1 ;;
PDF) curl -sL "$feed" > "/tmp/$(echo "$feed" | sed "s|.*/||;s/%20/ /g")" && zathura "/tmp/$(echo "$feed" | sed "s|.*/||;s/%20/ /g")" >/dev/null 2>&1 ;;
sxiv) curl -sL "$feed" > "/tmp/$(echo "$feed" | sed "s|.*/||;s/%20/ /g")" && sxiv -a "/tmp/$(echo "$feed" | sed "s|.*/||;s/%20/ /g")" >/dev/null 2>&1 ;;
vim) curl -sL "$feed" > "/tmp/$(echo "$feed" | sed "s|.*/||;s/%20/ /g")" && setsid -f "$TERMINAL" -e "$EDITOR" "/tmp/$(echo "$feed" | sed "s|.*/||;s/%20/ /g")" >/dev/null 2>&1 ;;
setbg) curl -L "$feed" > $XDG_CACHE_HOME/pic ; xwallpaper --zoom $XDG_CACHE_HOME/pic >/dev/null 2>&1 ;;
browser) setsid -f "$BROWSER" "$feed" >/dev/null 2>&1 ;;
lynx) lynx "$feed" >/dev/null 2>&1 ;;